tcp_hash_match() can take either an IPv4 (struct in_addr) or IPv6 (struct
in6_addr) address. It has two different paths for each of those cases.
However, its only caller has already constructed an equivalent inany
representation of the address, so we can have tcp_hash_match take that
directly and use a simpler comparison with the inany_equals() helper.
Signed-off-by: David Gibson <david(a)gibson.dropbear.id.au>
---
tcp.c | 16 ++++------------
1 file changed, 4 insertions(+), 12 deletions(-)
diff --git a/tcp.c b/tcp.c
index ca7f295..f566060 100644
--- a/tcp.c
+++ b/tcp.c
@@ -1177,25 +1177,17 @@ static int tcp_opt_get(const char *opts, size_t len, uint8_t
type_find,
/**
* tcp_hash_match() - Check if a connection entry matches address and ports
* @conn: Connection entry to match against
- * @af: Address family, AF_INET or AF_INET6
- * @addr: Remote address, pointer to in_addr or in6_addr
+ * @addr: Remote address
* @tap_port: tap-facing port
* @sock_port: Socket-facing port
*
* Return: 1 on match, 0 otherwise
*/
static int tcp_hash_match(const struct tcp_tap_conn *conn,
- int af, const void *addr,
+ const union inany_addr *addr,
in_port_t tap_port, in_port_t sock_port)
{
- const struct in_addr *a4 = inany_v4(&conn->addr);
-
- if (af == AF_INET && a4 && !memcmp(a4, addr, sizeof(*a4)) &&
- conn->tap_port == tap_port && conn->sock_port == sock_port)
- return 1;
-
- if (af == AF_INET6 &&
- IN6_ARE_ADDR_EQUAL(&conn->addr.a6, addr) &&
+ if (inany_equals(&conn->addr, addr) &&
conn->tap_port == tap_port && conn->sock_port == sock_port)
return 1;
@@ -1340,7 +1332,7 @@ static struct tcp_tap_conn *tcp_hash_lookup(const struct ctx *c,
inany_from_af(&aany, af, addr);
b = tcp_hash(c, &aany, tap_port, sock_port);
for (conn = tc_hash[b]; conn; conn = conn_at_idx(conn->next_index)) {
- if (tcp_hash_match(conn, af, addr, tap_port, sock_port))
+ if (tcp_hash_match(conn, &aany, tap_port, sock_port))
return conn;
}
--
2.38.1